Fahrenheit to Celsius

Level EASY

Given three values - Start Fahrenheit Value (S), End Fahrenheit value (E) and Step Size (W), you need to convert all Fahrenheit values from Start to End at the gap of W, into their corresponding Celsius values and print the table.

Input Format :
3 integers - S, E and W respectively 
Output Format :
Fahrenheit to Celsius conversion table. One line for every
 Fahrenheit and corresponding Celsius value. On Fahrenheit value and its
corresponding Celsius value should be separate by tab ("\t")
Constraints :
0 <= S <= 80
S <= E <=  900
0 <= W <= 40 
Sample Input 1:
0 
100 
20
Sample Output 1:
0   -17
20  -6
40  4
60  15
80  26
100 37
Sample Input 2:
20
119
13
Sample Output 2:
20  -6
33  0 
46  7
59  15
72  22
85  29
98  36
111 43
Explanation For Input 2:
We need need to start calculating the Celsius values for each of
the Fahrenheit Value which starts from 20.
So starting from 20 which is the given Fahrenheit start value, we need 
to compute its corresponding Celsius value which computes
to -6. We print this information as <Fahrenheit Value> a tab
space"\t" <Celsius Value> on each line for each step of 13
we take to get the next value of Fahrenheit and extend this
idea till we reach the end that is till 119 in this case.
You may or may not exactly land on the end value depending on the
steps you are taking.

Comments

  1. the constraints of s and w are not covered in this code

    ReplyDelete
  2. import java.util.Scanner;
    public class Solution {
    public static void main(String[] args) {
    Scanner s = new Scanner(System.in);
    int S = s.nextInt(); // 0
    int E = s.nextInt(); //100
    int dif = s.nextInt(); //10

    while(S<=E){
    int cel = ((S-32)*5)/9;
    System.out.println(S+"\t"+cel);
    S=S+dif;
    }
    }
    }


    I THINK THIS WILL SURELY HELP YOU.

    ReplyDelete
  3. This should do the job:

    #include
    using namespace std;

    int main()
    {
    int S,E,W,i,cd;
    cin>>S;
    cin>>E;
    cin>>W;
    while (((S>=0)&&(S<=80)) && ((E>=S)&&(S<=900)) && ((W>=0)&&(W<=40)))
    {
    while(S<=E)
    {
    for(i=S;i<=E;i+=W)
    {
    cd=(i-32)/1.8;
    cout<<i<<"\t"<<cd<<"\n";
    S+=W;
    }
    }
    }
    }

    ReplyDelete

Post a Comment

Please give us your valuable feedback

Popular posts from this blog

How to pass parameters in webhook?

Access and modify all the resources of our Wiki.js using WikiJS API